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Day 2/365; Car in Snow.

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Cars 2: What is a increase in speed of 2 cars upon a highway?
A automobile is roving during a consistent speed of seventeen m/s upon a highway. At a present this automobile passes an opening ramp, a second automobile enters a main road from a ramp. The second automobile starts from rest as well as has a consistent acceleration. What increase in speed contingency it maintain, so that a dual cars encounter for a primary time during a subsequent exit, that is 2.2 km away?

Best Reply:

Answer by Nigel Reynolds
Let Car A be a automobile roving during a consistent speed of seventeen m/s, as well as let Car B, be a automobile that starts from rest upon a opening ramp.
The pass to responding this complaint is to primary comprehend that in sequence for them to encounter during a subsequent exit 2.2 km away, a time it takes for Car A to get to a exit contingency be a same as a time it takes for Car B to get to a exit.
Car A is starting seventeen m/s, so it takes (2200m)/(17m/s) = 129.41 seconds for Car A to strech a subsequent exit.
Car B contingency have a same normal speed as Car A, that is seventeen m/s. If Car B’s increase in speed is constant, afterwards seventeen m/s = (final speed – primary speed)/2 = last speed /2.
So Car B’s last speed is 34 m/s, as a result it contingency say an increase in speed of (34/129.41) = .263 m/s^2

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